3x^2+7x=50

Solution for 3x^2+7x=50 equation:

3x^2+7x=50

We move all terms to the left:

3x^2+7x-(50)=0

a = 3; b = 7; c = -50;
Δ = b2-4ac
Δ = 72-4·3·(-50)
Δ = 649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{649}}{2*3}=\frac{-7-\sqrt{649}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{649}}{2*3}=\frac{-7+\sqrt{649}}{6}
$